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What will be the output of the following code?
public class MyClass {
public static void main(String[] args) {
int result = multiply(3, 4);
System.out.println(result);
}
public class MyClass {
public static void main(String[] args) {
int result = multiply(3, 4);
System.out.println(result);
}
public static int multiply(int a, int b) {
if (b == 0) {
return 0;
} else {
return a + multiply(a, b - 1);
}
}
}
if (b == 0) {
return 0;
} else {
return a + multiply(a, b - 1);
}
}
}
- a)0
- b)3
- c)4
- d)12
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
What will be the output of the following code?public class MyClass { p...
The given code is written in Java and it calculates the multiplication of two integers using a recursive function.
Let's break down the code and understand how it works:
1. The main method is the entry point of the code. It calls the multiply method with arguments 3 and 4 and stores the result in the variable 'result'.
2. The multiply method takes two integers, 'a' and 'b', as parameters. It is a recursive function that calculates the multiplication of 'a' and 'b' by reducing 'b' by 1 in each recursive call until 'b' becomes 0.
3. Inside the multiply method, it checks if 'b' is equal to 0. If it is, it means the multiplication is completed, so it returns 0 as the base case.
4. If 'b' is not equal to 0, it enters the else block. It recursively calls the multiply method with the same value of 'a' and 'b-1'. The return value of this recursive call is multiplied with 'a' and returned.
5. In each recursive call, 'b' is reduced by 1 until it becomes 0, at which point the base case is triggered, and the recursion stops.
6. Finally, the main method prints the value of 'result', which is the multiplication of 3 and 4.
Based on the above explanation, the output of the code will be 12.
Let's break down the code and understand how it works:
1. The main method is the entry point of the code. It calls the multiply method with arguments 3 and 4 and stores the result in the variable 'result'.
2. The multiply method takes two integers, 'a' and 'b', as parameters. It is a recursive function that calculates the multiplication of 'a' and 'b' by reducing 'b' by 1 in each recursive call until 'b' becomes 0.
3. Inside the multiply method, it checks if 'b' is equal to 0. If it is, it means the multiplication is completed, so it returns 0 as the base case.
4. If 'b' is not equal to 0, it enters the else block. It recursively calls the multiply method with the same value of 'a' and 'b-1'. The return value of this recursive call is multiplied with 'a' and returned.
5. In each recursive call, 'b' is reduced by 1 until it becomes 0, at which point the base case is triggered, and the recursion stops.
6. Finally, the main method prints the value of 'result', which is the multiplication of 3 and 4.
Based on the above explanation, the output of the code will be 12.
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Community Answer
What will be the output of the following code?public class MyClass { p...
The 'multiply' method is a recursive method that calculates the product of two numbers 'a' and 'b' using addition. If 'b' is 0, the method returns 0 (base case). Otherwise, it recursively calls itself with 'a' and 'b-1' as arguments, and the result is added to 'a'. The recursion continues until 'b' becomes 0.
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What will be the output of the following code?public class MyClass { public static void main(String[] args) { int result = multiply(3, 4); System.out.println(result); } public static int multiply(int a, int b) { if (b == 0) { return 0; } else { return a + multiply(a, b - 1); } }}a)0b)3c)4d)12Correct answer is option 'D'. Can you explain this answer?
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What will be the output of the following code?public class MyClass { public static void main(String[] args) { int result = multiply(3, 4); System.out.println(result); } public static int multiply(int a, int b) { if (b == 0) { return 0; } else { return a + multiply(a, b - 1); } }}a)0b)3c)4d)12Correct answer is option 'D'. Can you explain this answer? for EmSAT Achieve 2024 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about What will be the output of the following code?public class MyClass { public static void main(String[] args) { int result = multiply(3, 4); System.out.println(result); } public static int multiply(int a, int b) { if (b == 0) { return 0; } else { return a + multiply(a, b - 1); } }}a)0b)3c)4d)12Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the output of the following code?public class MyClass { public static void main(String[] args) { int result = multiply(3, 4); System.out.println(result); } public static int multiply(int a, int b) { if (b == 0) { return 0; } else { return a + multiply(a, b - 1); } }}a)0b)3c)4d)12Correct answer is option 'D'. Can you explain this answer?.
What will be the output of the following code?public class MyClass { public static void main(String[] args) { int result = multiply(3, 4); System.out.println(result); } public static int multiply(int a, int b) { if (b == 0) { return 0; } else { return a + multiply(a, b - 1); } }}a)0b)3c)4d)12Correct answer is option 'D'. Can you explain this answer? for EmSAT Achieve 2024 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about What will be the output of the following code?public class MyClass { public static void main(String[] args) { int result = multiply(3, 4); System.out.println(result); } public static int multiply(int a, int b) { if (b == 0) { return 0; } else { return a + multiply(a, b - 1); } }}a)0b)3c)4d)12Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the output of the following code?public class MyClass { public static void main(String[] args) { int result = multiply(3, 4); System.out.println(result); } public static int multiply(int a, int b) { if (b == 0) { return 0; } else { return a + multiply(a, b - 1); } }}a)0b)3c)4d)12Correct answer is option 'D'. Can you explain this answer?.
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